Question

How do you evaluate `6\div 6- ( 1+ 2- 2)`?

Answer 1

`0`

Explanation:

`"following the order of operations as set out in PEMDAS"`

`["Parenthesis (brackets),Exponents (powers"),`
`"Multiplication ,Division ,Addition ,Subtraction"]`

`rArr6-:6-(color(red)1)larrcolor(blue)" brackets"`

`=1-1larrcolor(blue)" division"`

`=0`