How do you evaluate #(-7/10+0.15)-:(-0.125)#?

1 Answer
Shwetank Mauria
Apr 27, 2016

#(-7/10+0.15)-:(-0.125)=4.4#

Explanation:

#(-7/10+0.15)-:(-0.125)#

= #(-70/100+15/100)-:(-125/1000)#

= #(-55/100)-:(-125/1000)#

= #55/100-:125/1000=55/100xx1000/125#

= #(11cancel(55))/cancel100xx(10cancel(1000))/(25cancel(125))#

= #11xx(2cancel(10))/(5cancel(25))=22/5=(22xx2)/(5xx2)=44/10=4.4#

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