# How do you evaluate (- 7) ^ { 2} \div ( - 3- - 10) ^ { 2}?

Apr 6, 2017

#### Explanation:

First combine the terms in the parenthesis

${\left(- 7\right)}^{2} / {\left\{- 3 - \left(- 10\right)\right\}}^{2} = \frac{49}{+ 7} ^ 2$

a negative time a negative = a positive
$\left(- 7\right) \times \left(- 7\right) = + 49$

$\left(-\right) \times \left(- 10\right) = + 10$

$- 3 + 10 = + 7$

$\frac{49}{+ 7} ^ 2 = \frac{49}{49}$

$\frac{49}{49} = 1$

Apr 7, 2017

#### Answer:

$1$

#### Explanation:

${\left(- 7\right)}^{2} \div {\left(- 3 - - 10\right)}^{2}$

$\textcolor{w h i t e}{a a a a a a a a a a a a a a}$$- 3$
$\textcolor{w h i t e}{a a a a a a a a a a a a a}$$- 10$ $-$
$\textcolor{w h i t e}{a a a a a a a a a a a a a}$$- - -$
$\textcolor{w h i t e}{a a a a a a a a a a a a a a}$$+ 7$

$\therefore \left(- 7 \times - 7\right) \div {\left(7\right)}^{2}$

$\therefore \left(- 7 \times - 7\right) \div 7 \times 7$

$\therefore 49 \div 49 = 1$