# How do you evaluate (7+3^2)/(4^2*2)?

Dec 24, 2016

$\frac{1}{2}$

#### Explanation:

We first calculate the term with exponents:

$\frac{7 + \textcolor{red}{{3}^{2}}}{\textcolor{b l u e}{{4}^{2}} \cdot 2} \to \frac{7 + \left(\textcolor{red}{3 \cdot 3}\right)}{\left(\textcolor{b l u e}{4 \cdot 4}\right) \cdot 2} \to \frac{7 + \textcolor{red}{9}}{\textcolor{b l u e}{16} \cdot 2}$

Next we can add the terms in the numerator:

$\frac{7 + \textcolor{red}{9}}{\textcolor{b l u e}{16} \cdot 2} \to \frac{16}{\textcolor{b l u e}{16} \cdot 2}$

Now, we can simplify the numerator and denominator:

$\frac{16}{\textcolor{b l u e}{16} \cdot 2} \to \frac{\textcolor{b l u e}{\cancel{\textcolor{b l a c k}{16}}}}{\cancel{\textcolor{b l u e}{16}} \cdot 2} \to \frac{1}{2}$