How do you evaluate #(7+3^2)/(4^2*2)#?

1 Answer
Dec 24, 2016

Answer:

#1/2#

Explanation:

We first calculate the term with exponents:

#(7 + color(red)(3^2))/(color(blue)(4^2)*2) -> (7 + (color(red)(3*3)))/((color(blue)(4*4))*2) -> (7 + color(red)(9))/(color(blue)(16)*2)#

Next we can add the terms in the numerator:

#(7 + color(red)(9))/(color(blue)(16)*2) -> 16/(color(blue)(16)*2)#

Now, we can simplify the numerator and denominator:

#16/(color(blue)(16)*2) -> color(blue)(cancel(color(black)(16)))/(cancel(color(blue)(16))*2) -> 1/2#