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How do you evaluate #(7^ { 3/ 4} ) ^ { - 2/ 9}#?

1 Answer

Answer:

#=> (7)^(-1/6)#

Explanation:

https://www.youtube.com/watch?v=ARLS2TmFT94

As per Laws of Indices,

#(a^m)^n) = a ^(m * n)#

#(7^(3/4))^-(2/9) = (7)^((3/4) * (-2/9))#

#=> (7)^(-6/36) = (7)^(-1/6)#

#(7)^(-1/6)# can be rewritten as #.^6sqrt(1/7)#.

I hope that helps!