How do you evaluate #[7-(3-6(5-3)+2)]+7#?

1 Answer
Mar 3, 2018

Answer:

in his type of question we first have to solve the inner brackets
the answer is #21#

Explanation:

so first we will solve the inner brackets
#[7-(3-6(5-3)+2)]+7#

the 5-3 is in the inner brackets so #5-3=2#

#[7-(3-6(2)+2)]+7#
multiplying #6# by #2# which equals #12#

#[7-(3-12+2)]+7#
calculating numbers in the bracket

#[7-(-7)]+7#
if we have a negative outside a bracket, it will change the signs of all the numbers in the bracket. if it is #-# it will become + and if it is + it will become -

so #7+7+7# #=21#