# How do you evaluate [(7-5)^5/8]-4?

First, note that the parentheses mean that $7 - 5$ should be computed first to get $7 - 5 = 2$. Then raise that to the fifth power to get ${\left(7 - 5\right)}^{5} = {2}^{5} = 32$ (powers come before divisions in order of operations). Then divide by 8 to get $\frac{{\left(7 - 5\right)}^{2}}{8} = \frac{32}{8} = 4$. Finally, subtract 4 to get $\frac{{\left(7 - 5\right)}^{2}}{8} - 4 = 4 - 4 = 0$.
The outer brackets $\left[\right]$ are not technically needed in the notation.