Question

How do you evaluate `8^(-2/3)* 64^(1/6)`?

Answer 1

Let's first look at the `64^(1/6)`

Explanation:

Since `64=8^2` we might as well write:

`8^(-2/3)*(8^2)^(1/6)=` `8^(-2/3)*8^(2*1/6)=`

`8^(-2/3)*8^(1/3)=` `8^(-2/3+1/3)=8^(-1/3)`

This may also be written as `1/root 3 8`