How do you evaluate #[(8+5) (6-2) ^2] - (4*17div2)#?

1 Answer
Jun 10, 2015

Answer:

Actually the square brackets in the first part aren't neccessary.
We first clear the brackets:

Explanation:

#=(13*4^2)-(4*17:2)#
Then the powers:
#=(13*16)-(4*17:2)#
Then the multiplications and divisions (two groups!):
#=208-34#
Finally the adding and subtracting:
#=174#

Note that all the brackets I put in the explanation are superfluous, they were just put there for clarity (what belongs together?).