# How do you evaluate 8P3?

The permutation formula is ""_nP_r=(n!)/((n-r)! Since $n = 8$ and $r = 3$ We can just substitute values and solve:
""_nP_r=(n!)/((n-r)!)=(8!)/((8-3)!)=(8cdot7cdot6cdotcancel(5cdot4cdot3cdot2cdot1))/cancel(5cdot4cdot3cdot2cdot1)
$8 \cdot 7 \cdot 6 = 336$