# How do you evaluate ((9 - 2)^2 + 4) + 4^2?

Jun 11, 2015

You can use the sequence of priority normally called PEMDAS,

#### Explanation:

I would start from the brackets and the squares:
$\left({\left(9 - 2\right)}^{2} + 4\right) + {4}^{2} =$
$\left({\left(7\right)}^{2} + 4\right) + 16 =$
$= \left(49 + 4\right) + 16 =$
Now I solve all the sums and subtractions:
$= 53 + 16 = 69$