Question

How do you evaluate `9^(3/2)`?

Answer 1

See below

Explanation:

`9^(3/2)=sqrt( 9·9·9)=sqrt(3^2·3^2·3^2)= sqrt9·sqrt9·sqrt9=3·3·3=27`

Other way would be

`9^(3/2)=(3^cancel2)^(3/(cancel 2))=3^3=27`

Answer 2

`27`

Explanation:

`"using the "color(blue)"law of exponents"`

`•color(white)(x)a^(m/n)=(root(n)a)^m`

`rArr9^(3/2)=(root(2)9)^3=(3)^3=27`

Answer 3

`27`

Explanation:

`9^(3/2)`

is equal to

`(9^(1/2))^3`

is equal to

`(\sqrt(9))^3`

is equal to

`3^3`

is equal to

`27`