How do you evaluate #90= 10( 2y + 3)#?

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Answer 1 · 2018-05-02T00:48:38

#y=3#

#90=10(2y+3) rarr# You could evaluate using the distributive property or you could divide each side by #10#

#9=2y+3#

#2y=6#

#y=3#

Using the distributive property:

#90=10*2y+10*3#

#90=20y+30#

#20y=60#

#y=3#