How do you evaluate #91\times \frac { 3} { 13} #? Prealgebra Arithmetic and Completing Problems Order of Operations 1 Answer Tony B Dec 14, 2016 21 Explanation: #91xx3xx1/13# # = 273/13# # =273-:13# #=21# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Check #" "21# #ul(" "13) larr" multiply"# #color(white)(.)210# #ul(color(white)(..)63) larr" add"# #color(white)(,)273# Answer link Related questions What is #5-3*(-2) + |-3|#? What is #(3 * 10)^2 -: 5 - 4#? What is #2+2(2)^2(5)+ 8#? What is #14.3 * 2.1 * 8.9#? What is #8+(8+8-:4)+5^2#? How do you use PEMDAS to simplify #3 times 2 - (8+1) #? How do you simplify #3^4+2^3+8(4xx2-5) #? How do you simplify #4times3^2+3times4^2+2(3times4)^2#? How do you solve #30-5(4^2-8รท4-5*2)#? What is #7-3(-8-2) + 6 -:2#? See all questions in Order of Operations Impact of this question 1437 views around the world You can reuse this answer Creative Commons License