# How do you evaluate a^ 5 b^ -6 for a=3 and b=2?

${a}^{5} \cdot {b}^{-} 6 = {\left(\frac{a}{b}\right)}^{5} \cdot \frac{1}{b} = {\left(\frac{3}{2}\right)}^{5} \cdot \frac{1}{2} = {3}^{5} / {2}^{6} = \frac{243}{64} = 3 \frac{51}{64} \approx 3.8$