How do you evaluate #[(a-b)*c]2*d# given a=25, b=14, c=3, d=7?

1 Answer
Oct 31, 2016

#924#

Explanation:

#[(a-b)xxc]2xxd, a=25, b=14, c=3, d=7#

To evaluate, we need to replace the letters with numbers and then perform the operation.

First, we have to subtract #a# from #b#. This will give us #11#.

#[(25-14)xx3]2xx14 = (11xx3)2xx14#

Then we must perform the multiplications. It doesn't matter which order we perform these in, as multiplication is commutative #(axxbxxc=axxcxxb=cxxbxxa)#.

#11xx3xx2xx14=924#