Question

How do you evaluate `(abs(3-3)--4)times5`?

Answer 1

`20`

Explanation:

PEMDAS needed:

P: Parenthesis
E: Exponents
M: Multiplication
D: Division
A: Addition
S: Subtraction

First solve what is in the parenthesis:

`( |0| + 4 ) xx 5 larr` two minuses make a plus and the absolute value of `0` is `0`

`=(0 + 4) xx 5`

`=(4) xx 5`

`=20`