# How do you evaluate #abs(-4)timesabs(-12)/3times-abs3/abs6#?

##### 1 Answer

Nov 27, 2016

#### Explanation:

The

#color(blue)"absolute value function"# is always positive.The reason being that it denotes the distance a value is from zero and distance is always positive.

#" Thus" |-4|=|4|=4# as 4 and - 4 are both 4 units from zero.

#rArr|-4|xx|-12|/3xx-|3|/|6|" can be expressed as"#

#4xx12/3xx-3/6#

#=4xx4xx-1/2=cancel(16)^8xx-1/cancel(2)^1=-8#