How do you evaluate $a n t i ln (- 0.7831)$ $antiln(-0.7831)$ ?

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Answer 1 · 2017-02-19T16:34:35

$e^{- 0.7831}$ $e^-0.7831$

The antilog is the inverse function of the log. In this case, the inverse function of $ln$ $ln$ is the exponential $e$ $e$ .

How do you evaluate antiln(-0.7831)antiln(−0.7831)antiln(-0.7831)?