How do you evaluate #c^ -3(16^ -2)# for c=4?

1 Answer
Don't Memorise
Mar 22, 2016

#=color(green)(4^-7#

Explanation:

#c^ - 3 (16^-2)# , #color(blue)(c=4#

Substituting the value of #c# given:

#=color(blue)(4^ - 3) (16^-2)#

note: #16 # can be written as # 4^2#

#=color(blue)((4^ - 3)) (4^(2 * (-2)))#

#=color(blue)((4^ - 3)) (4^ -4)#

  • by property
    #color(blue)(a^m * a^n = a^(m+n)#

#color(blue)((4^ - 3)) (4^ -4) = 4^(( -3 + ( -4))#

#=color(green)(4^-7#

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