Question

How do you evaluate `cos((11pi)/6)`?

Answer 1

`sqrt3/2`

Explanation:

Trig table and trig unit circle -->
`cos ((11pi)/6) = cos (-pi/6 + (12pi)/6) = cos (-pi/6 + 2pi) =`
`= cos (-pi/6) = cos (pi/6) = sqrt3/2`