Question

How do you evaluate `cot((11pi)/6)`?

Answer 1

`cot(11pi)/6 = -sqrt3`

Explanation:

`cot((11pi)/6)`

Recall the identity `cottheta=costheta/sintheta`

Using the unit circle, `cos((11pi)/6)=sqrt3/2` and `sin((11pi)/6)=-1/2`

`cot((11pi)/6)=frac{sqrt3/2}{-1/2}=sqrt3/2 * -2/1=-sqrt3`