How do you evaluate #cot((3pi)/2)#?

2 Answers
May 4, 2015

If you consider an angle to be positioned
centered on the origin of the Cartesian plane
with a base arm along the positive X-axis
then
the terminal arm of #(3pi)/2# is along the negative Y-axis.

The #cot((3pi)/2)# is the value of #x# divided by the value of #y# for any point along the terminal arm.
#x=0# for all points along the terminal arm

#cot((3pi)/2)=0#

May 5, 2015

#cot (3pi)/2 = cot(pi/2 + pi) = cot pi/2 #
On the trig unit circle #cot (pi/2) = 0, then#
#cot ((3pi)/2) = 0#