# How do you evaluate (d+1)(d-1+6) d=2?

Oct 15, 2015

The answer is 21

#### Explanation:

How to get the answer:

1. Replace the variable with the value $\implies$ $\left(2 + 1\right) \left(2 - 1 + 6\right)$
2. First you would do $\left(2 + 1\right) = 3$
3. The problem is now $\left(3\right) \left(2 - 1 + 6\right)$
4. Now you do $2 - 1$ . You do this instead of doing $1 + 6$ because you do subtraction and addition from left to right
5. Then you have $\left(3\right) \left(1 + 6\right)$ = $\left(3\right) \left(7\right)$
6. Parentheses tell you to multiply so the answer you should get is twenty-one

I took a picture of the elongated steps because I describe how to solve inside the parentheses