# How do you evaluate #e^ln3#?

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Jan 20, 2017

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Consider ** #e^ln3#**:

We know that a natural logarithm is

#color(red)ln = color(blue)log_e#

Therefore **1**

All that's left over is the 3

So 1•3 = 3 (The answer)

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Feb 12, 2015

But to have:

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