How do you evaluate #e^ln3#?

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Jan 20, 2017

Answer:

#e^ln3# = 3

Explanation:

Consider #e^ln3#:

We know that a natural logarithm is

#color(red)ln = color(blue)log_e#

Therefore #log_e(e)# = 1

All that's left over is the 3

So 1•3 = 3 (The answer)

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Gió Share
Feb 12, 2015

Try to write it as a log:
#ln(x)=ln3# which is: #x=e^(ln(3))#
But to have:
#ln(x)=ln3# means that #x=3# or: #e^(ln(3))=3#

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