# How do you evaluate -( \frac { 1} { 2} ) ^ { 2} + 3+ 2?

Mar 4, 2018

$\frac{19}{4}$

#### Explanation:

First, raise the fraction to a power of 2 by raising the numerator and denominator to that power
${1}^{2} / {2}^{2}$ = $- \frac{1}{4}$

$3 + 2 = 5$
so we get $- \frac{1}{4} + 5$
$- \frac{1}{4} + \frac{20}{4}$
= $\frac{19}{4}$