Question

How do you evaluate `g(b^2+1)` if `g(x)=(3-x)/(5+x)`?

Answer 1

`g(b^2+1)=(2-b^2)/(6+b^2)` or `g(b^2+1)=-(b^2-2)/(b^2+6)`

Explanation:

In the notation `g(x)` you know that whatever is put in the parentheses is what replace for `x`. In this situation, because it says `g(b^2+1)`, you replace every `x` in the function with `b^2+1`. You would then simplify the function further.
If `g(x) = (3-x)/(5+x)`,
then `g(b^2+1)=(3-(b^2+1))/(5+(b^2+1))=(2-b^2)/(6+b^2)`