How do you evaluate $g (m + 1)$ $g(m+1)$ if $g (x) = 2 x^{2} - 4 x + 2$ $g(x)=2x^2-4x+2$ ?

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How do you evaluate $g (m + 1)$ $g(m+1)$ if $g (x) = 2 x^{2} - 4 x + 2$ $g(x)=2x^2-4x+2$ ?

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Answer 1 · 2016-11-23T05:32:46

$g (m + 1) = 2 m^{2}$ $g(m+1)=2m^2$

Explanation:

$x = m + 1$ $x=m+1$
$g (x) = 2 x^{2} - 4 x + 2$ $g(x)=2x^2-4x+2$
$g (x) = 2 (x^{2} - 2 x + 1)$ $g(x)=2(x^2-2x+1)$
$g (x) = 2 (x - 1) (x - 1)$ $g(x)=2(x-1)(x-1)$
$g (m + 1) = 2 ((m + 1) - 1) ((m + 1) - 1)$ $g(m+1)=2((m+1)-1)((m+1)-1)$
$g (m + 1) = 2 (m) (m)$ $g(m+1)=2(m)(m)$
$g (m + 1) = 2 m^{2}$ $g(m+1)=2m^2$

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How do you evaluate $g (m + 1)$ $g(m+1)$ if $g (x) = 2 x^{2} - 4 x + 2$ $g(x)=2x^2-4x+2$ ?

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