Question

How do you evaluate `(h^{2}+3)(h^{3}-2h^{2}+h)`?

Answer 1

`(h^2+3)(h^3-2h^2+h)=h^5-2h^4+4h^3-6h^2+3h`

Explanation:

`(h^2+3)(h^3-2h^2+h)`

= `h^2(h^3-2h^2+h)+3(h^3-2h^2+h)`

= `h^2xxh^3-2h^2xxh^2+hxxh^2+3h^3-3xx2h^2+3xxh`

= `h^5-2h^4+ul(h^3+3h^3)-6h^2+3h`

= `h^5-2h^4+4h^3-6h^2+3h`