Question

How do you evaluate if possible the 6 trigonometric functions of the real number `t= (-2pi)/3`?

Answer 1

Find the 6 trig function values of `t = (-2pi)/3`

Explanation:

Unit circle and Trig table of special arcs -->
`sin t = sin ((-2pi)/3) = sin (pi/3 - pi) = - sin pi/3 = - sqrt3/2`
`cos t = cos (pi/3 - pi) = - cos pi/3 = - 1/2`
`tan t = sin t/(cos t) = (-sqrt3/2)(-2/1) = 1/sqrt3 = sqrt3/3.`
`cot t = 3/sqrt3 = sqrt3`
`sec = 1/(cos) = -2`
`csc x = 1/(sin) = -(2sqrt3)/3`