Question

How do you evaluate: `int_{-2}^3 x^2 - 3 dx`?

Answer 1

`-10/3`

Explanation:

STEP 1: Take the antiderivative of the function
=`[1/3x^3 - 3x]_-2^3`

STEP 2: Evaluate between the founds
= `[(1/3) (3^3) - 3(3)] - [(1/3) (-2)^3 - 3(-2)]`

STEP 3: Compute your final answer
= `[9 - 9] - [-8/3 + 6]`
= `8/3 - 18/3`
= `-10/3`