How do you evaluate #j(2a)# if #j(x)=1-4x^3#?

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Answer 1 · 2016-11-11T21:32:55

#j(2a)=-32a^3+1#

Plug in #2a# into the equation #j(x)#:

#j(2a) = 1-4(2a)^3#
#=1-4(8a^3)#
#=1-32a^3#

Answer 2 · 2016-11-11T21:33:53

#j(2a)=1-32a^3#

If #j(color(red)x)=1-4color(red)(x)^3#
then
#color(white)("XXX")j(color(red)(2a))=1-4 * (color(red)(2a))^3#

#color(white)("XXXX")= 1-4 * (8a^3)#

#color(white)("XXXX")=1-32a^3#