# How do you evaluate Log_(1050) (1+x)=137?

May 10, 2018

...the base seems very big...but anyway:

#### Explanation:

We can use the definition of log to write it as an exponential getting rid of the log as:

$x + 1 = {1050}^{137}$

and:

$x = {1050}^{137} - 1$

that is a BIG number!!!

(something like $8 \times {10}^{413}$!!!!)