How do you evaluate #Log_(1050) (1+x)=137#?

1 Answer
May 10, 2018

...the base seems very big...but anyway:

Explanation:

We can use the definition of log to write it as an exponential getting rid of the log as:

#x+1=1050^(137)#

and:

#x=1050^(137)-1#

that is a BIG number!!!

(something like #8xx10^(413)#!!!!)