How do you solve 2logx4=16?

1 Answer
Feb 19, 2015

It depends upon the base of your logarithm. Let us assume that the base is a number a.

You have:

2logax4=16

logax4=162 the power of 4 can go as multiplier of log:

4logax=8 and again:

logax=84

logax=2

x=a2

Now, you can choose the value of a. Normally (when it is not specified) it should be 10, so if this is the case you get:
x=102=100