How do you solve $2 log x^4 = 16$ ?

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Answer 1 · 2015-02-19T15:58:59

It depends upon the base of your logarithm. Let us assume that the base is a number $a$ .

You have:

$2log_ax^4=16$

$log_ax^4=16/2$ the power of $4$ can go as multiplier of log:

$4log_ax=8$ and again:

$log_ax=8/4$

$log_ax=2$

$x=a^2$

Now, you can choose the value of $a$ . Normally (when it is not specified) it should be $10$ , so if this is the case you get:
$x=10^2=100$

How do you solve 2 log x^4 = 162 log x^4 = 16?