How do you evaluate #log_15 1#?

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Answer 1 · 2016-08-31T14:24:13

Zero

#2^3=8# which can also be written as #log_2(8)=3#

This is I think quite easy to remember

So given #log_15(1)=x# where you want to find X
Rewrite as #15^x=1#

Any number to the power of zero =1

So X=1

Answer 2 · 2016-08-31T14:31:37

#log_15 1 = 0#

The question we need to ask with log format is..

"What index/power of 15 will give 1?"

Any base raised to the power of 0 will give 1.

#15^0 = 1#

Log form and index form are interchangeable.

#log_15 1 = 0 hArr 15^0 = 1#

Remember that #0^0 # is undefined., so #log 0# is undefined.