How do you evaluate #log_16 8#?

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Answer 1 · 2017-02-20T14:41:09

#log_16 8=3/4#

Let #log_16 8=x#, then from definition of logarithm,

#16^x=8#

or #(2^4)^x=2^3#

or #2^(4x)=2^3#

or #4x=3#

i.e. #x=3/4#

Hence #log_16 8=3/4#