How do you evaluate log_3 1?

2 Answers
Aug 15, 2016

I found that it is equal to zero:

Explanation:

You may use the definition of log:
log_ba=x
so that: a=b^x

we now need to find our x in:
log_3(1)=x

using our definition we see that the only possible value for x is zero because:
1=3^0

Aug 15, 2016

log_3 1 = 0

Explanation:

Written in log form, the question being asked is,"

"1 is which power of 3? " 3^0 =1

Or

"Using a base of 3, what index will give 1 as the answer?"
3^0 =1

Log form and index form are interchangeable.

log_3 1 = x " " rArr 3^x = 1

x = 0