How do you evaluate $log_3 18$ ?

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Answer 1 · 2016-05-19T01:44:00

$= log_3(9 xx 2)$

$= log_3(9) + log_3(2)$

$= log9/log3 + log2/log3$

$= log3^2/log3 + log2/log3$

$= 2cancel(log3)/cancel(log3) + log2/log3$

$= 2 + log_3(2)$

Hopefully this helps!

How do you evaluate log_3 18log_3 18?