Question

How do you evaluate `\log _ { 6} ( 36\times 6^ { - 7} )`?

Answer 1

`log_6 (36xx6^(-7))=-5`

Explanation:

WE can use the identity `log_aa^m=m` and may be `log_a(pxxq)=log_ap+log_aq`

Here we have `log_6 (36xx6^(-7))`

= `log_6 (6^2xx6^(-7))`

= `log_6 6^(2-7)`

= `log_6 6^(-5)`

= `-5`