How do you evaluate #log_7(343)#?

2 Answers
Nov 29, 2015

Answer:

#log_7(343) = 3#

Explanation:

If #x=log_7(343)#
then we are looking for a value of #x# such that #7^x= 343#

#7^1=7#
#7^2=49#
#7^3=343#

#rArr x=3#

In most cases a question like this would require the use of a calculator. In this case the question was obviously set up for a direct solution.

Nov 30, 2015

Answer:

3

Explanation:

#log_7(343)=log_7(7^3)#
#=3log_7(7)#
#=3*1#
#=3#