# How do you evaluate log_7 7?

${\log}_{7} \left(7\right) = 1$
If ${a}^{m} = b$ in exponential form, we can write it in logarithmic form as ${\log}_{a} b = m$.
Let ${\log}_{7} \left(7\right) = x$ and writing it in exponential form, we get ${7}^{x} = 7 = {7}^{1}$ or $x = 1$
Note - In fact for all values of $a$, we have ${\log}_{a} a = 1$