# How do you evaluate log_7 (7^(2x))?

Oct 18, 2016

${\log}_{7} \left({7}^{2 x}\right) = 2 x$

#### Explanation:

As ${\log}_{a} {p}^{n} = n {\log}_{a} p$ and ${\log}_{a} a = 1$

${\log}_{7} \left({7}^{2 x}\right)$

= $2 x {\log}_{7} 7$

= $2 x \times 1 = 2 x$