Question

How do you evaluate `sec((11pi)/6)`?

Answer 1

`(2sqrt3)/3`

Explanation:

`sec ((11pi)/6) = 1/(cos ((11pi)/6)`
Trig table and unit circle -->
`cos ((11pi)/6) = cos (-pi/6 + (12pi)/6) = cos (-pi/6 + 2pi) =`
`= cos (-pi/6) = cos (pi/6) = sqrt3/2`
There for:
`sec ((11pi)/6) = 2/sqrt3 = (2sqrt3)/3`