Question

How do you evaluate `sec(60)+csc^2(pi/3)`?

Answer 1

`10/3`

Explanation:

Since `secalpha=1/cosalpha`

and `cscalpha=1/sinalpha`

the given expression becomes:

`1/cos 60+1/sin^2(pi/3)`

Since `cos 60=1/2` and `sin (pi/3)=sqrt(3)/2`,

`2+4/3=10/3`