How do you evaluate $sin ((23pi) / 3)$ ?

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Answer 1 · 2016-05-22T22:09:19

$-sqrt3/2$

Trig table and trig unit circle -->
$sin ((23pi)/3) = sin (-pi/3 + (24pi)/3) = sin (-pi/3 + 8pi) =$
$= sin (-pi/3) = - sin (pi/3) = - sqrt3/2$

How do you evaluate sin ((23pi) / 3) sin ((23pi) / 3) ?