How do you evaluate $sin ((25pi)/6)$ ?

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Answer 1 · 2016-06-21T11:16:45

$1/2$

notice that $(25 pi) / 6 = ((24 + 1) pi) / 6 = 4 pi + pi /6$

so you're just looking at $pi/6$ . you can ignore the 2 full cycles of $2 pi$

$sin (pi / 6) = 1/2$

How do you evaluate sin ((25pi)/6)sin ((25pi)/6)?