Question

How do you evaluate sin(3π/2)?

Answer 1

`-1`

Explanation:

The direction #theta=(3pi)/2 separates 3rd and 4th quadrants.

Sine is negative in these quadrants.

`sin(pi+theta)=sin(2pi-theta)=-sin theta`.

`sin((3pi)/2)=sin (pi+pi/2)=sin(2pi-pi/2)=-sin (pi/2)=-1`