Question

How do you evaluate `sin ((5pi)/4)`?

Answer 1

`-sqrt2/2`

Explanation:

Trig table of special arcs, unit circle, property of supplementary arcs -->
`sin ((5pi)/4) = sin (pi/4 + (4pi)/4) = sin (pi/4 + pi) = - sin (pi/4) =- sqrt2/2`