# How do you evaluate sqrt(b^2-4ac) for a=1, b=7, c=-3?

$\sqrt{61}$
$\Delta = \sqrt{{b}^{2} - 4 a c} = \sqrt{{7}^{2} - 4 \cdot 1 \cdot \left(- 3\right)} = \sqrt{49 + 12} = \sqrt{61}$