How do you evaluate #sum_(n=2)^6(2n-1)#?
1 Answer
Sep 14, 2016
Explanation:
This appears to be an arithmetic series, but since there are only 5 terms, you might as well just write the terms out by moving the index of summation through from 2 to 6 and then add them :\
If you want to force the arithmetic series formula, then you may identify the common difference as 2, the first term as 3, and 5 terms in total in this convergent series to get